6 / 10Simplification-EasyQuantitative AptitudeSimplify: (13−14)÷(13+14)×7\left(\dfrac{1}{3}-\dfrac{1}{4}\right) \div \left(\dfrac{1}{3}+\dfrac{1}{4}\right) \times 7(31−41)÷(31+41)×7ShareA111B17\frac{1}{7}71C777D712\frac{7}{12}127Show answer & explanationAnswerACorrect answer111 Explanation13−14=112\frac{1}{3}-\frac{1}{4}=\frac{1}{12}31−41=121 and 13+14=712\frac{1}{3}+\frac{1}{4}=\frac{7}{12}31+41=127. Dividing gives 112÷712=17\frac{1}{12} \div \frac{7}{12} = \frac{1}{7}121÷127=71, and multiplying by 777 gives 111.Written by ExamHoot EditorialPublished 12 Aug 2026 · Updated 27 Aug 2026Previous · 5 of 10Simplify:Next · 7 of 10Simplify using the identity (a+b)^2 = a^2+2ab+b^2 :All 10 Simplification- questionsAll (10)Easy (10)1.Simplify:2.Simplify:3.Simplify:4.Simplify using BODMAS:5.Simplify:6.Simplify:7.Simplify using the identity (a+b)^2 = a^2+2ab+b^2 :8.Simplify:9.Simplify:10.Simplify: