Find the value of $?$ in the following equation: $\sqrt[3]{140608} \times \sqrt{1849} - \frac{114.28\% \text{ of } 2100}{15} = ?^2 - 179$

1) $\sqrt[3]{140608} = 52$. 2) $\sqrt{1849} = 43$. $52 \times 43 = 2236$. 3) $114.28\% = 100\% + 14.28\% = 1 + \frac{1}{7} = \frac{8}{7}$. $\frac{8}{7} \times 2100 = 2400$. $\frac{2400}{15} = 160$. 4) LHS: $2236 - 160 = 2076$. $2076 = ?^2 - 179 \implies ?^2 = 2076 + 179 = 2255$, which is not a perfect square integer, hence None of these.