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A vessel contains 40 liters of a mixture of milk and water in the ratio 5:35:3. If 8 liters of the mixture is removed and replaced with water, and this process is repeated once more, what is the final ratio of milk to water in the vessel?

A vessel contains 40 liters of a mixture of milk and water in the ratio 5:35:3. If 8 liters of the mixture is removed and replaced with water, and this process is repeated once more, what is the final ratio of milk to water in the vessel?

  1. 2:32:3

  2. 3:23:2

  3. 5:35:3

  4. 3:53:5

  5. 1:11:1

Show answer & explanation

Correct answer

2:32:3

Explanation

Initial milk = 40×58=2540 \times \frac{5}{8} = 25 L. After each removal and replacement, milk remaining factor = 1840=0.81 - \frac{8}{40} = 0.8. After 2 operations, milk = 25×(0.8)2=1625 \times (0.8)^2 = 16 L. Water = 4016=2440 - 16 = 24 L. Final ratio milk:water = 16:24=2:316:24 = 2:3.

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