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For two events A and B, P(A)=0.5P(A) = 0.5, P(B)=0.4P(B) = 0.4 and P(A∩B)=0.2P(A\cap B) = 0.2. What is P(Ac∩B)P(A^c \cap B), the probability that B occurs but A does not?

For two events A and B, P(A)=0.5P(A) = 0.5, P(B)=0.4P(B) = 0.4 and P(A∩B)=0.2P(A\cap B) = 0.2. What is P(Ac∩B)P(A^c \cap B), the probability that B occurs but A does not?

  1. 0.20.2

  2. 0.30.3

  3. 0.10.1

  4. 0.40.4

Show answer & explanation

Correct answer

0.20.2

Explanation

P(Ac∩B)=P(B)−P(A∩B)=0.4−0.2=0.2P(A^c \cap B) = P(B) - P(A\cap B) = 0.4 - 0.2 = 0.2.

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  5. 5.A box contains 3 red, 5 green, and 2 yellow balls.
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  12. 12.In a box, there are 3 defective and 7 non-defective items.
  13. 13.A card is drawn from a well-shuffled deck of 52 cards.
  14. 14.Two dice are rolled simultaneously.
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  16. 16.A bag contains 5 white and 3 black balls.
  17. 17.From a group of 6 men and 4 women, a committee of 3 persons is to be formed.
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  19. 19.A die is thrown twice.
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  21. 21.A fair coin is tossed 5 times.
  22. 22.Two fair dice are rolled together.
  23. 23.Three fair dice are rolled simultaneously.
  24. 24.Two cards are drawn successively without replacement from a well-shuffled standard deck of 52 cards.
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