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What is the result of evaluating `(2 + 3) * 4 == 20 || !(5 > 3) && (6 / 2 == 3)` in Java?

  1. true

  2. false

  3. Compilation error

  4. Runtime exception

Show answer & explanation

Correct answer

true

Explanation

`(2+3)*4` = 20, so `20 == 20` is true. Due to operator precedence, `||` has lower precedence than `&&`, and `!` has higher than `&&`. So expression is `true || (false && true)` = `true || false` = true.

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All 10 Java -operators questions

  1. 1.Given the expression `int a = 5; int b = 10; int c = ++a * b-- + a;`, what is the value of `c` after evaluation?
  2. 2.What is the result of evaluating `(2 + 3) * 4 == 20 || !(5 > 3) && (6 / 2 == 3)` in Java?
  3. 3.Given `int x = 7; int y = 3; int z = x ^ y;` and then `z = z << 1;`, what is the final value of `z`?
  4. 4.Which of the following expressions evaluates to `true` for all non-negative integers `n`?
  5. 5.Consider `short s = 10; s = s + 5;` and `short t = 10; t += 5;`.
  6. 6.What is the output of the following code?
  7. 7.Given `int x = 5; x = x++ + ++x;`, what is the final value of `x`?
  8. 8.What is the value of `(int) (3.9 + 5.1 / 2.0)` in Java?
  9. 9.Given `boolean a = true; boolean b = false; boolean c = a | b & !a;`, what is the value of `c`?
  10. 10.Which of these expressions is guaranteed to produce arithmetic overflow?